#include<iostream>

using namespace std;
int daytab[2][13] = {
    {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
    {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
};

bool isLeapYear(int year) {
    if (year % 100 != 0 && year % 4 == 0 || year % 400 == 0)
        return true;
    return false;
}

char a[9], b[9];

int main() {
    //n为第一个日期相对于0000 00 00的差值，n1为为第二个的差值
    int year, month, day, year1, month1, day1, n, n1;
    while (cin >> a >> b) {
        n = n1 = 0;
        sscanf(a, "%4d%2d%2d", &year, &month, &day);//格式化读入
        sscanf(b, "%4d%2d%2d", &year1, &month1, &day1);
        for (int i = 0; i <= year; i++) {//记录年差值
            if (isLeapYear(i)) {
                n += 366;
            } else n += 365;
        }
        for (int i = 1; i < month; i++) {//记录月差值
            n += daytab[isLeapYear(year)][i];
        }
        n += day;//记录日差值
        for (int i = 0; i <= year1; i++) {
            if (isLeapYear(i)) {
                n1 += 366;
            } else n1 += 365;
        }
        for (int i = 1; i < month1; i++) {
            n1 += daytab[isLeapYear(year1)][i];
        }
        n1 += day1;
        cout << abs(n - n1) + 1 << endl;//差值相减取绝对值+1即可
    }
    return 0;
}



